Question

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2x=(x-3)^2

Answer 1

Răspuns:

Explicație pas cu pas:

2x=x^2-6x+9

-> X^2(il voi scrie ca x2 de acum) - 6x+9-2x=0

x2-8x+9=0

delta=64-4*1*9

delta=64-36

delta=28

x1=(8+rad28)/2

x2=(8-rad28)/2

Answer 2

(x-3)^2=2x

x^2-6x+9=2x

x^2-6x-2x+9=0

x^2-8x+9=0

a=1

b=-8

c=9

delta=b^2-4ac

delta=64-36

delta=28

$x1 = \frac{ - b + \sqrt{delta} }{2a}$

$x1 = \frac{8 + \sqrt{28} }{2}$

$x1 = \frac{ 8 + 2 \sqrt{7} }{2}$

$x1 = 4 + \sqrt{2}$

$x2 = \frac{ - b - \sqrt{delta} }{2a}$

$x2 = \frac{8 - 2 \sqrt{7} }{2}$

$x2 = 4 - \sqrt{2}$