Question

Rezolvă ecuația: (x+2)(x+3)(x+4)(x+5)
dau coroana​

Answer 1

Răspuns:

$\bf\red{x^{4} +14x^{3}+71x^{2} +154x+120 }$

Explicație pas cu pas:

$(x+2)(x+3)(x+4)(x+5)=\\=(x^{2}+3x+2x+6)(x+4)(x+5) =\\=(x^{2}+5x+6)(x+4)(x+5) =\\=(x^{3}+4x^{2} +5x^{2} +20x+6x+24 )(x+5)=\\=(x^{3}+9x^{2} +26x+24 )(x+5)=\\=x^{4}+5x^{3}+9x^{3}+45x^{2} +26x^{2} +130x+24x+120=\\=\bf\red{x^{4} +14x^{3}+71x^{2} +154x+120 }$