Question

rezolva ecuatiile : a) x+7/3=18/2; b) x-5=13/71

Answer 1

$\\ a) \quad \text{x}+\dfrac{7}{3} = \dfrac{18}{2} \\ \\\text{x}+\dfrac{7}{3} = 9 \\ \\ \text{x} = 9-\dfrac{7}{3} \\ \\ \text{x} = \dfrac{9\cdot 3}{3}-\dfrac{7}{3} \\ \\ \text{x} = \dfrac{27-7}{3} \\ \\ \text{x} = \dfrac{20}{3}$

$\\ b) \quad \text{x}-5 = \dfrac{13}{71} \\ \\ \text{x} = \dfrac{13}{71}+5 \\ \\ \text{x} = \dfrac{13}{71}+\dfrac{5\cdot 71}{71} \\ \\ \text{x} = \dfrac{13+5\cdot 71}{71} \\ \\ \text{x} = \dfrac{13+355}{71} \\ \\ \text{x} = \dfrac{368}{71}$

Answer 2

a) x=18/2-7/3
x=54/6-14/6
a=40/6
a=20/3
b) x=13/71+5
x=13/71+355/71
a=368/71