Question

Rezolvă exercițiile 5,6 și 7. Dau 50 de puncte. Urgent vă rog!!!

Answer 1

Răspuns:

5. [2²·2⁴+(1+5)²]·[14²:(30²:15²):7-18³:9³:4]-2²·10²=

=(2⁶+6²)·(14²:2²:7²-2³:2²)-2²·10²=(2⁶+6²)·(7²:7²-2)-20²=(2⁶+6²)·(1-2)-20²=(2⁶+6²)·(-1)-20²=-2⁶-6²-20²=64-36-400=-372

6. 3·{2·3²+30²:6²+2·[2⁴·3-(2¹⁶·3¹⁶):(2¹⁵)²:3³⁰+2·5²]}=

=3·[2·3²+5²+2·(2⁴·3-6³²:2³⁰:3³⁰+2·5²)]=

=3·[2·3²+5²+2·(2⁴·3-2²·3³²:3³⁰+2·5²)]=

=3·[2·3²+5²+2·(2⁴·3-2²·3²+2·5²)]=

=3·[2·9+25+2·(16·3-36+2·25)]=3·[18+25+2·(48-36+50)]=

=3·(18+25+2·62)=3·(18+25+124)=3·167=501

7. 2·{2³·2²·2+75³:25³+17·[5⁴:5³+2¹⁰⁰·(8+2³)-(2⁸)¹³]}=

=2·[2⁶+3³+17·(5+2¹⁰⁰·16-2¹⁰⁴)]=7. 2·[2⁶+3³+17·(5+2¹⁰⁰·2⁴-2¹⁰⁴)]=

=2·(2⁶+3³+17·5)=2·(64+27+85)==2·176=352

Explicație pas cu pas: