rezolva in doua moduri!
(334+335+336ori2
9ori(50004+1987)
2.se stie ca : m=31,n=8,p=500,r=492.
calculeaza:
(m+p+r)ori n=. (doua metode)
(p+r)ori(2ori m+3ori n+4orip)
va rog mult ajutatima imi trebuie repede va rog!!!!
Răspunsuri la întrebare
Răspuns de
1
metoda 1
(334+335+ 336)×2=1005×2=2010
metoda 2
(334×2)+(335×2)+(336×2)=668+670+672=2010
ex2
met.1
(m+p+r)×n=(31+500+492)×8=1023×8=8184
met2
(m×n)+(p×n)+r×n)=(31×8)+(500×8)+(492×8)=248+4000+ 3936=8184
(p+r)×(2×m+3×n+4×p)
(500+8)×(2×31+3×8+4×500)=508×(62+24+2000)=508×2086=1059688
sau
(508×2×31)+(508×3×8)+(508×4×500)=31496+12192+1016000=1059688
(334+335+ 336)×2=1005×2=2010
metoda 2
(334×2)+(335×2)+(336×2)=668+670+672=2010
ex2
met.1
(m+p+r)×n=(31+500+492)×8=1023×8=8184
met2
(m×n)+(p×n)+r×n)=(31×8)+(500×8)+(492×8)=248+4000+ 3936=8184
(p+r)×(2×m+3×n+4×p)
(500+8)×(2×31+3×8+4×500)=508×(62+24+2000)=508×2086=1059688
sau
(508×2×31)+(508×3×8)+(508×4×500)=31496+12192+1016000=1059688
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