Question

Rezolva in doua moduri, folosind propietatile inmultirii
a) 16x(160+14)=
b) 4x125+4x83=

Answer 1

Răspuns:

16*(160+14)=16*174=2.784

16*160+16*14=2.560+224=2784

4*125+4*83=500+332=832

4*(125+83)=4*208=832

Answer 2

Răspuns:

primul mod 1 ex

16×(160+14)=2784

1) 160+14=174

2) 174×16=2784

al doilea mod 1 ex

16×160+16×14=2784

1)16×160=2560

2) 16×14=224

3) 2560+224=2784

primul mod 2 ex

4×125+4×83=832

1) 125×4=500

2) 4×83=332

3) 500+332=832

al doilea mod 2 ex

4×(125+83)=832

1) 125+83=202

2) 4×208=832