Question

rezolva in multimea nr intregi ecuatia (3 -6÷5) la patrat ÷9÷5 -0,2=x÷10

Answer 1

      
$(3-6:5)^2 :9:5-0,2=x:10 \\ \\ (3- \frac{6}{5} )^2 :9:5-0,2= \frac{x}{10} \\ \\ ( \frac{15-6}{5} )^2 :9:5-0,2= \frac{x}{10} \\ \\ ( \frac{9}{5} )^2 :9:5-0,2= \frac{x}{10} \\ \\ \frac{81}{25} :9:5-0,2= \frac{x}{10} \\ \\ \frac{81}{25*9}:5-0,2= \frac{x}{10} \\ \\ \frac{9}{25}:5-0,2= \frac{x}{10}$


$\frac{9}{25*5}-0,2= \frac{x}{10} \\ \\ \frac{9}{125}- \frac{2}{10} = \frac{x}{10} \\ \\ \frac{9}{125}- \frac{1}{5} = \frac{x}{10} \\ \\ \frac{9}{125}- \frac{25*1}{25*5} = \frac{x}{10} \\ \\ \frac{9}{125}- \frac{25}{125} = \frac{x}{10} \\\\\frac{9-25}{125}= \frac{x}{10}\\\\\frac{-16}{125}= \frac{x}{10} \\ \\ x= \frac{-16*10}{125} =\frac{-16*2}{25} =\boxed{\frac{-32}{25}}=\boxed{-1,28}$