Question

rezolva inecuatiile in R:
3(x-2)+x<4x+1
3(1-x)+2(2-2x)<0
5(x+2)-x>3(x-1)+x
-(4-x)<2(3+x)
4(x+8)-7(x-1)<12
va rog mult mult ajutatima
multumesc mult

Answer 1

3x-6+x<4x+1,4x-6<4x+1 deci x poate fi orice x din R, 3-3x+4-4x=7-7x<0,7x>0,x>o, 5x+10-x>3x-3+x, 2x>-13,x>-13/2, -4+x<6+2x,x>-10, 4x+32-7x+7=-3x+39<12,-3x>-27, x>9