Question

rezolva înmulțirea numerelor întregii ecuații 5x{3+4x[1+2(xsupra3-4)]}+11=46​

Answer 1

Răspuns:

5x{3+4x[1+2(x/3-4)]}+11=46​

3+4[1+2(x/3-4)=46-11:5

4[1+2(x/3-4)=7-3

1+2(x/3-4)=4:4

2(x/3-4)=1-1

x/3-4=0

x/3=4

x=4·3

x=12

Answer 2

Răspuns: $\red{\bf x = 12}$

Explicație pas cu pas:

$\bf 5\cdot\bigg\{3+4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]\bigg\}+11=46$

$\bf 5\cdot\bigg\{3+4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]\bigg\}=46-11$

$\bf 5\cdot\bigg\{3+4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]\bigg\}=35~~~\bigg|:5$

$\bf 3+4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]=7$

$\bf 4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]=7-3$

$\bf 4\cdot\bigg[1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)\bigg]=4~~~\bigg|:4$

$\bf 1+2\cdot\bigg(\dfrac{x}{3}-4\bigg)=1$

$\bf 2\cdot\bigg(\dfrac{x}{3}-4\bigg)=1-1$

$\bf 2\cdot\bigg(\dfrac{x}{3}-4\bigg)=0$

$\bf \dfrac{2x}{3}-8=0$

$\bf \dfrac{2x}{3}=8~~~\bigg|\cdot 3$

$\bf 2x=24~~~~\bigg|:2$

$\red{\boxed{\bf x = 12}}$