Question

rezolva prin metoda reducerii,sistemele:{2x+3y=5};{5x+2y=-2};{-6x+4y-1=0};{x+0,5y-1=0}

Answer 1

2x+3y=5 /*2
5x+2y=-2 /*-3
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4x+6y=10
-15x-6=6
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-11x /=16
x=-16/11
2x+3y=5
2*(-16/11)+3y=5
-32/11+3y=5
-32+33y=55
33y=55+32
33y=87
y=87/33
y=29/11
b)  -6x+4y=0
        x+0,5y=0 /*6
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-6x+4y=0
6x+3y=0
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/     7y=0
y=0
-6x+4y=0
-6x+4*0=0
-6x+0=0
-6x=0
x=0