Question

rezolva prin metoda substitutiei x/3+y/2=1 si 2(x+1)+y=4

Answer 1

$\left\{\begin{matrix} \frac{x}{3} + \frac{y}{2} = 1 \: | \times 6\\ \\ 2(x + 1) + y = 4\end{matrix}\right.$

$\left\{\begin{matrix} 2x + 3y = 6\\ 2x + 2 + y = 4\end{matrix}\right.$

$\left\{\begin{matrix} 2x + 3y = 6\\ 2x + y = 4 - 2\end{matrix}\right.$

$\left\{\begin{matrix} 2x + 3y = 6\\ 2x + y = 2\end{matrix}\right.$

$2x + y = 2$

$y = 2 - 2x$

$2x + 3y = 6$

$2x + 3(2 - 2x) = 6$

$2x + 6 - 6x = 6$

$2x - 6x = 6 - 6$

$- 4x = 0 \: | \times ( - 1)$

$4x = 0$

$x = \frac{0}{4}$

$x = 0$

$y = 2 - 2x$

$y = 2 - 2 \times 0$

$y = 2 - 0$

$y = 2$