Question

Rezolva sistemele:
a) x√2 + y√2 = 2√6
x√3 - y√2 = 0


b) 2x+y-1 pe x+3 = 1
3x-y = -2

Answer 1

a)
x√2 + y√2 = 2√6
x√3 - y√2 = 0

x√2+x√3  = 2√6
x(√2+√3)  = 2√6
x= 2√6/(√2+√3)= 2√6(√2-√3)/(√2+√3)(√2-√3)= 2√6(√2-√3)/(2-3)=
= (2√12-2√18)/(2-3)=(4√3-6√2)/(-1)=6√2-4√3

x√2 + y√2 = 2√6    impartim la √2
x + y = 2√3
y= 2√3-(6√2-4√3)=2√3-6√2+4√3=4√3-4√2=4(√3-√2)


b)
(2x+y-1)/(x+3) = 1
3x-y = -2

2x+y-1=x+3
3x-y = -2

x+y=4
3x-y = -2
4x=4-2=2
x=2/4=1/2
y=4-1/2=7/2