Question

Rezolva sistemele prin metoda substitutiei :
a) x-3y=4
2x+y-1=0


b) x=y+2
6x-4y=8


Prin metoda reducerii:
a) 4x-6y=-2
X+3y=4



b) x+2y=o
4x+2y=2.


Prin metoda mixta:
a) x+y=16
X-y=8




b) -3x+y=1
X-y-7=0

Answer 1

Ai rezolvarea in atasament