Question

Rezolvare completa urgent!!
DAU COROANA​

Answer 1

Explicație pas cu pas:

18/(x+3)€N <=> x+3€D18 in N =>

x+3€{1,2,3,6,9,18} =>

x€{-2,-1,0,3,6,15} cum x€N => x€{0,3,6,15} =>

A={0,3,6,15}

9/(x+3)€Z <=<x+3€D9 in Z =>

x+3€{-9,-3,-1,1,3,9} =>

x€{-12,-6,-4,-2,0,6} => B={-12,-4,-2,0,+-6}

(3x+2)/(2x+3)€N <=> 2x+3|3x+2

2x+3|3x+2 => 2x+3|6x+4

2x+3|2x+3=>2x+3|6x+9

Le scadem:

2x+3|6x+9-6x-4 => 2x+3|5 Cum ne cere x€N este suficient sa cautam 2x+3€N

Deci 2x+3€D5 in N =>

2x+3€{1,5} =>

2x€{-2,2} => x€{-1,1} cum x€N => x€{1} => C={1}