Question

Rezolvare la asta va rog: aflati x,y,z stiind ca sunt invers proportionale cu nr 0,5 ;0,(3) si 0,1(6) iar 3x+4y-2z=30

Answer 1

0,5 = 5/10 = 1/2

0,(3) = 3/9 = 1/3

0,1(6) = (16-1)/90 = 15/90 = 1/6

x*1/2 = y*1/3 = z*1/6 = k

x/2 = y/3 = z/6 = k

x = 2k

y = 3k

z = 6k

3x + 4y - 2z = 30

3*2k + 4*3k - 2*6k = 30 => 6k + 12k - 12k = 30 => 6k = 30 => k = 5

Atunci x = 2k = 10

y = 3k = 15

z = 6k = 30