Question

rezolvarea ecuatiei 0.92=2x/1+x

Answer 1

   
[tex]\displaystyle \\ 0,92=\frac{2x}{1+x} \\ \\ 2x = 0,92(1+x) \\ 2x = 0,92 + 0,92x \\ 2x - 0,92x = 0,92 \\ 1,08x = 0,92 \\ \\ x = \frac{0,92}{1,08} = \frac{92}{108} = \frac{4 \times 23 }{4 \times 27} = \boxed{\frac{23 }{27} }[/tex]

Answer 2

0,92=2x/(1+x)
2x=0,92+0,92x
2x-0,92x=0,92
1,08x=0,92
x=0,92/1,08
x=0,85(aproximativ)