Question

Rezolvarea ecuației:

[48+50•100: (28:a+3•2)-14]•[(50-4•5)+(143-4•6)]=42 316

a=2
a=8
a=5​.

Answer 1

Răspuns:

a=2

Explicație pas cu pas:

Rezolvarea ecuației:

[48+50•100: (28:a+3•2)-14]•[(50-4•5)+(143-4•6)]=42 316  ⇒

[48+5000: (28:a+6)-14]•[(50-20)+(143-24)]=42 316  ⇒

[48+5000: (28:a+6)-14]•[30+119]=42 316  ⇒

[48+5000: (28:a+6)-14]•149=42 316 ⇒[48+5000: (28:a+6)-14]=42316:149  ⇒[48+5000: (28:a+6)-14]=284  ⇒[48-14+5000:(28:a+6)]=284  ⇒

34+5000:(28:a+6)=284  ⇒5000:(28:a+6)=284-34  ⇒5000:(28:a+6)=250  ⇒(28:a+6)=5000:250  ⇒(28:a+6)=20  ⇒28:a=20-6  ⇒28:a=14  ⇒a=28:14  ⇒a=2