Question

Rezolvarea la ex 4 si raspunsul

Answer 1

$E_{echivalent}=E_1+E_2=6V\\R_{S}=R_1+R_2=22$Ω

$r_{echivalent}=r_1+r_2=2$Ω

E=IR+Ir

$I=\frac{E}{R+r}=\frac{6}{24}=\frac{1}{4}=0,25A$