Question

Rezolvata va rog!!! Dau 50 de puncte!

Answer 1

Răspuns:

a.

p=m,px100/m,i---> m,p= 85x50/100g=42,5g Mgpur

.

A,Mg=24g/mol

miu,HCl=36,5g/mol  ;  miuMgCl2=95g/mol

Vm=22,4 l/mol

24g......2x36,5g......95g...........22,4 l

Mg    +  2HCl--->     MgCl2 + H2

42,5..........x.................y..............z

b.  x=m=129,3gHCl=md

c=mdx100/ms---> ms= 129,3x100/20g=646,5g sol

c.    z=V=39,7 l  H2

d.   y=m=168,2 gMgCl2=md

m,apa= msHCl-md,HCl=646,5-129,3>=517,2g

ms,sare=md,sare+m.apa=168,2+517,2=>685,4g

c= md,sarex100/m,s= 168,2x100/685,4=24,5%

Explicație: