Question

Rezolvati:
[2,(3)-1,2]:0,68-0,(6)

Answer 1

$[2,(3)-1,2]\div0,68-0,(6) =$

$(2\cdot \frac{3}{9} - \frac{12}{10}) \div \frac{68}{100} - \frac{6}{9} =$

$(\frac{6}{9} - \frac{1}{5} ) \div \frac{17}{25} - \frac{1}{3} =$

$(\frac{1}{3} - \frac{1}{5} ) \div \frac{17}{25} - \frac{1}{3} =$

$\frac{1}{3}-\frac{1}{5} = \frac{5}{15}-\frac{3}{15} = \frac{5-3}{15} = \frac{2}{15}$

$\frac{2}{15}\div \frac{17}{25}-\frac{1}{3} =$

$\frac{2}{15}\div \frac{17}{25} =\frac{2}{3}\cdot \frac{5}{17} =\frac{2}{3}\cdot \frac{5}{17} =\frac{2\cdot \:5}{3\cdot \:17} =\frac{10}{51}$

$\frac{10}{51}-\frac{1}{3} =\frac{10}{51}-\frac{17}{51} =\frac{10-17}{51} =\frac{-7}{51} =-\frac{7}{51}$