Question

Rezolvati 2x+3 supra x^2+x+1 mai mare sau egal cu 1​

Answer 1

Răspuns:

$\frac{2x + 3}{ {x}^{2} + x + 1 } \geqslant 1 \\ 2x + 3 \geqslant {x}^{2} + x + 1 \\ {x}^{2} + x + 2 \geqslant 0 \\ {x}^{2} + 2x - x + 2 \geqslant 0 \\ x(x + 2) - (x + 2) \geqslant 0 \\ (x + 2)(x - 2) \geqslant 0 \\ {x}^{2} - 4 \geqslant 0 \\ {x}^{2} \geqslant 4 \\ x \geqslant - 4 \: si \: 4$