Question

Rezolvati : ( 5 supra 2x+1 -1 supra x+1 -1 supra 2x la patrat +3x+1) impartit la 3x-6 supra 2x la patrat -x-1

Answer 1

[$\frac{5}{2x+1}$-$\frac{1}{x+1}$-$\frac{1}{2x^2-x-1}$]:$\frac{3x-6}{2x^2-x-1}$=[$\frac{5}{2x+1}$-$\frac{1}{x+1}$-$\frac{1}{(x+1)(2x+1)}$]:$\frac{3(x-2)}{(2x+1)(x-1)}$=[$\frac{5x+5-2x-1-1}{(2x+1)(x+1)}$-$] x [tex] \frac{(2x+1)(x-1)}{3(x-2)}$ = $\frac{3(x+1)}{(x+1)(2x+1)}$ x $\frac{(2x+1)(x-1)}{3(x-2)}$=$\frac{x-1}{x-2}$

am adus la acelasi factor comun (x+1)(2x+1) apoi la final dupa calcule am simplificat