Question

Rezolvati : a) ( 1 supra 4 + 1 intreg 1 supra 4 ) × 1 supra 6 ;
b) ( 7 supra 3 + 2 supra 3 - 1 supra 3 ) : ( 7 supra 9 - 5 supra 9 )

Answer 1

a)(1/4+1 1/4)×1/6

(1/4+5/4)×1/6

3/2×1/6

1/2×1/2

1/4 ✔

b)(7/3+2/3-1/3):(7/9-5/9)

8/3:2/9

8/3×9/2

4×3

12 ✔

Answer 2

a) (1/4+1 1/4)x1/6=

(1/4+5/4)x1/6=

6/4x1/6=

=1/4

b) (7/3+2/3-1/3):(7/9-5/9)=

(9/3-1/3):2/9=

8/3:2/9=

8/3x9/2=

4x3=

=12

Succes!