Question

rezolvati aceasta problema :
5 supra 24 + 7 supra 18

Answer 1

[tex]\it \dfrac{5}{24}+\dfrac{7}{18} =\dfrac{5}{6\cdot4}+\dfrac{7}{6\cdot3}=\dfrac{1}{6} \cdot\dfrac{5}{4}+\dfrac{1}{6}\cdot\dfrac{7}{3} = \dfrac{1}{6}\cdot\left(\dfrac{^{3)}5}{\ 4}+\dfrac{^{4)}7}{\ 3}\right) = \\\;\\ \\\;\\ =\dfrac{1}{6}\cdot\dfrac{15+28}{12}=\dfrac{1}{6}\cdot \dfrac{43}{12}=\dfrac{43}{72}[/tex]