Question

Rezolvati aceste exericitii va rog frumos. Multumesc!

Answer 1

c) $\frac{2*5+4}{5}$ + $\frac{2*4+1}{4}$ *x = $\frac{3*5+2}{5}$
$\frac{14}{5}$ + $\ frac{9}{4}$ *x= $\frac{17}{5}$
aducem la acelasi numitor, adica la 20
56+45x= 68
45x=12
x=$\frac{12}{45}$

e) ($\frac{17}{6}$ - $\frac{4}{3}$ ) : (x+1)= $\frac{5}{2}$
aducem a doua fractie la acelasi numitor, adica 6
$\frac{17-8}{6}$ :(x+1)= $\frac{5}{2}$
 o sa scriu cu / impartirea
9/6 : (x+1) = 5/2
3/2* 2/5=x+1
3/5=x+1
x=-2/5

g) 7/9 + (2x-1)/6 = 11/6 - 11/6 *x
(2x-1) /6 -11x/6 =11/6 - 7/9
aducem la acelasi numitor
(2x-1-11x)/6 = (99-42)/54
(-9x-1)/6= 57/54
aducem iar la acelasi numitor
9(-9x-1)=57
-91x-9=57
-91x=66
x=-66/91
Sper ca sunt corecte si ca te-am ajutat.