Question

rezolvati dupa procedeul 2, inegalitatile x+15<27 ,20+x<101

Answer 1

x+15<27

x<27-15

x<12

x€{0,1,2,3,4,5,6,7,8,9,10,11}

20+x<101

x<101-20

x<81

x€{0,1,2,3....80}

Answer 2

a) x+15<27-> x< 12-> x apartine {11,10,9,....,-∞}.............. b) 20+x<101-> x< 81-> x apartine { 80,79,78,...,-∞}