Question

Rezolvati ecuatia:
0,(6)x+2x-0,(3)=4-2(x+1)+3,(6)

Answer 1

[tex]0,(6)x+2x-0,(3)=4-2(x+1)+3,(6)\\ \\ \frac{2x}{3}+2x-\frac{1}{3}=4-2x-2+3\frac{6}{9}\\ \\ \frac{8x-1}{3}=2-2x+\frac{11}{3}|\cdot 3\\ 8x-1=6-6x+11\\ 14x=18\\ x=\frac{18}{14}\Rightarrow \boxed{x=\frac{9}{7}}}[/tex]