Question

rezolvati ecuatia 125+{14x[40+(x+240):40]-34}x17=47147 trebuie sa il aflu pe x din paranteza rotunda urgent

Answer 1

125+{14·[40+(×+240):40]-34}·17=47147
{14·[40+(×+240):40]-34}·17=47147-125=47022
14·[40+(×+240):40]-34=47022:17=2766
14·[40+(×+240):40]=2766+34=2800
40+(×+240):40=2800:14=200
(×+240):40=200-40=160
×+240=160·40
×+240=6400
×=6400-240
×=6160