Question

rezolvati ecuatia
2•{[78+13•(6+x)]:26-3}+6=2006

Answer 1

[tex]\displaystyle \\ 2 \cdot \{[78+13 \cdot (6+x)]:26-3\}+6=2006 \\ 2 \cdot \{[78+13 \cdot (6+x)]:26-3\}=2006-6 \\ 2 \cdot \{[78+13 \cdot (6+x)]:26-3\}=2000 \\ \\ \{[78+13 \cdot (6+x)]:26-3\}= \frac{2000}{2} \\ \\ { [78+13 \cdot (6+x)]:26-3 }= 1000 \\ { [78+13 \cdot (6+x)]:26 }= 1000 +3\\ { [78+13 \cdot (6+x)]:26 }= 1003\\ 78+13 \cdot (6+x)= 1003 \cdot 26 \\ 78+13 \cdot (6+x)= 26078 \\ 13 \cdot (6+x)= 26078 -78 \\ 13 \cdot (6+x)= 26000 \\ \\ (6+x)=\frac{26000}{13} \\ \\ 6+x = 2000 [/tex]

$x = 2000 -6 = \boxed{1994 }$