Question

Rezolvati ecuatia 2x-1 supra - x supra 3= x+ 3 supra 6 ∈ R

Answer 1

$\frac{2x-1}{\frac{-x}{3}}=\frac{x+3}{6}$

$\left(2x-1\right)\cdot \:6=\frac{-x}{3}\left(x+3\right$

$\frac{2x-1}{\frac{-x}{3}}=\frac{x+3}{6} \\ \\ (2x-1)\cdot6\cdot3=-\frac{x}{3}\cdot(x+3)\cdot3\\ \\ 18\cdot(2x-1)=-x(x+3)\\ \\ 36x-18=x^{2} -3x\\ \\ -x^{2} -3x=36x-18\\ \\ -x^{2} -39x+18=0$

x₁=(-39+3√177)/2

x₂=(-39-3√177)/2