Question

Rezolvați ecuatia: a=[1-1,(6)]la a2a×1,5-1,8(3). Dau COROANA....

Answer 1

Salut.

$a = [1 - 1,(6)]^{2} \cdot 1,5 - 1,8(3)$

$\displaystyle{a= (1 - \frac{16-1}{9})^{2} \cdot \frac{15}{10} - \frac{183-18}{90} }$

$\displaystyle{ a =( \frac{9}{9}-\frac{15}{9})^{2} \cdot \frac{15}{10} - \frac{165}{90}}$

$\displaystyle{ a = (\frac{-6}{9})^{2} \cdot \frac{3}{2}-\frac{11}{6} }$

$\displaystyle{ a = (\frac{-2}{3})^{2} \cdot \frac{9}{6}-\frac{11}{6} }$

$\displaystyle{a = \frac{4}{9} \cdot \frac{9}{6} - \frac{11}{6} }$

$\displaystyle{a=\frac{4}{6}-\frac{11}{6} }$

$\boxed{a=\frac{-7}{6}}$

- Lumberjack25

Answer 2

Răspuns:

Explicație pas cu pas:

1,(6) = (16 - 1)/9 = 15/9 = 5/3

1 - 5/3 = 3/3 - 5/3 = -2/3

1,8(3) = (183 - 18)/90 = 165/90 = 33/18 = 11/6

1,5 = 15/10 = 3/2

a = (-2/3)^2 * 3/2 - 11/6 = 4/9 * 3/2 - 11/6 = 2/3 - 11/6 = 4/6 - 11/6 = -7/6