Question

Rezolvati ecuatia cu delta
${b}^{2} - 4ac$
$|x + 2|=|2x - 6|$​

Answer 1

$|x+2| = |2x-6| \\ \\\sqrt{(x+2)^2} = \sqrt{(2x-6)^2} \\ \\ (x+2)^2 = (2x-6)^2 \\ x^2+4x+4= 4x^2-24x+36 \\ 3x^2-28x+32 = 0 \\ \Delta = 28^2-4\cdot 3\cdot 32 = 400 \\ \\ x_{1,2} = \dfrac{28\pm 20}{6} \Rightarrow x_1 = \dfrac{8}{6},\quad x_2 = 8$