Question

Rezolvati ecuatia
(m-4)m+3=-1

Answer 1

(m-4)m+3=-1
m²-4m+3=-1
m²-4m+4=0
Δ=b²-4ac
Δ=(-4)²-4*1*4=16-16=0
x1,2=-b+-√Δ/2a=-(-4)+-0/2=4+-0/2
x1=4+0/2=4/2=2
x2=4-0/2=4/2=2
Δ=0 ⇒ x1=x2

Answer 2

$(m-4)m+3=-1 \\ \\ m^2-4m+3+1=0 \\ \\ m^2-4m+4=0 \\ \\(m-2)^2=0 \Rightarrow m-2=0 \Rightarrow \boxed{m=2}~.$