Question

rezolvati ecuatia: numerele fiind de forma:
xy+yz+xz=246
numerele fiind scrise in baza 10

Answer 1

xy=10×x+y;
yz=10×y+z;
xz=10×x+z;
xy+yz+xz=246⇔10×x+y+10×y+z+10×x+z=246⇔20×x+11×y+2×z=246⇔x=10; y=4; z=2