Question

Rezolvati ecuatia $iz^{2} +(3+i)z+2-2i=0$, z apartine C

Answer 1

delta= (3+i)² - 4i(2-2i) = 9 +6i -1 - 8i +8i² = 8 + 6i - 8i - 8= -2i

$\sqrt{ - 2i} = 1 - 1i$

$z1 = \frac{ - 3 - i - 1 + 1i}{2} = \frac{ - 4}{2} = - 2 \\ \\ z2 = \frac{ - 3 - i + 1 - 1i}{2} = \frac{ - 2 - 2i}{2} = - 1 - i$

Answer 2

Răspuns:

Explicație pas cu pas: