Question

rezolvati ecuatia
$\sin2x = \sqrt{3} \times sinx$
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Answer 1

Răspuns:

salut,

rezolvati IN CE MULTIME??

si, "rezolvati" si MAI CE/CUM???

Explicație pas cu pas:

2sinxcosx-√3sinx=0

sinxcosx-(√3/2) sinx=0

sinx(cosx-√3/2)=0

sinx=0...x=kπ

cosx=√3/2...x= 2kπ+(-1)^k arccos(√3/2= 2kπ+(-1)^k*(π/6)

x∈kπ ∪2kπ+(-1)^k arccos(√3/2= 2kπ+(-1)^k*(π/6)