Question

rezolvati ecuatia (x-1)la a doua-(3-x)la a doua=2[(x la a doua +6)-(x+2)la a doua]

Answer 1

(x - 1)² - (3 - x)² = 2[(x² + 6) - (x + 2)²]
x² - 2x + 1 - (9 - 6x + x²) = 2[x² + 6 - (x² + 4x + 4)]
x² - 2x + 1 - 9 + 6x - x² = 2(x² + 6 - x² - 4x - 4)]
4x -8 = 2(- 4x + 2)
4x - 8 = - 8x + 4
4x + 8x = 8 + 4
12x = 12
x = 12/12
x = 1

Answer 2

(x-1)^2 -(3-x)^2 = 2 [(x^2+6) - (x+2)^2]
x^2 -2x +1 - (9-6x+x^2) = 2 [ x^2+6 - (x^2 +4x +4)]
x^2-2x+1 -9 +6x-x^2 = 2 ( x^2 +6 -x^2 -4x -4)
4x -8 = 2 ( 6-4x-4)
4x-8 = 2 (2-4x)
4x-8= 4 -8x
12x=12=> x=1