Question

Rezolvați ecuația:
(x-√3)²=(2√3-4)²
URGENT

Answer 1

x²-2√3x+3 = 12-16√3+16

x²-2√3x+16√3 = 28-3

x²+14√3-25 = 0

Δ = b²-4ac = 588+100 = 688

x1 = (-b+√Δ)/2a = (-14√3+4√43)/2 = 2(-7√3+2√43)/2 = -7√3+2√43

x2 = (-b-√Δ)/2a = (-14√3-4√43)/2 = 2(-7√3-2√43)/2 = -7√3-2√43

Answer 2

(x-√3)²= (2√3-4)²

√(x-√3)²= √(2√3-4)²

|x-√3|= |2√3-4|

x-√3>0

√(x-√3)² =√(2√3 - 4)²

x-√3=I2√3 - 4I

x-√3=-2√3 + 4

x = 4 - √3

x-√3<0

√(x-√3)² =√(2√3 - 4)²

-x+√3=I2√3 - 4I

-x+√3=-2√3 + 4

x = 3√3 - 4