Question

Rezolvati ecuatia
        
x+3$(2-x)^{2}$ - 4 $(x-3)^{2}$ = $(2x-5)^{2}$ - 5 $(x-4)^{2}$ + 10

Answer 1

x + 3(4 -4x+x²) -4(x² -6x +9) = 4x² -20x +25 -5(x² -8x +16) +10
x+ 12 -12x +3x² -4x² +24x -36= 4x² -20x +25 -5x² +40x -80 +10

x -12x +3x² -4x² +24x -4x² +20x +5x²-40x = 25 -80 +10-12 +36
-7x = -21
7x=21
x=21/7
x=3