Question

Rezolvați ecuațiaA (x-1)^2-2(x-2)=(x-3)(x+3)
B.rezolvati inecuația 4(x+3)<2(x+5)+8

Answer 1

$(x - 1)^{2} - 2(x - 2) = (x - 3)(x + 3 \\ {x}^{2} - 2x + 1 - 2x + 4 = {x}^{2} - 9 \\ {x}^{2} - 4x + 5 = {x}^{2} - 9 \\ {x}^{2} - 4x - {x}^{2} = - 9 - 5 \\ - 4x = - 14 \\ x = - 14 \div 4 \\ x = \frac{7}{2} \\ s =( \frac{7}{2} ) \\ \\ \\ 4(x + 3) < 2(x + 5) + 8 \\ 4x + 12 < 2x + 10 + 8 \\ 4x + 12 < 2x + 18 \\ 4x - 2x < 18 - 12 \\ 2x < 6 | \div 2 \\ x < 3 \\ s = (2.1.0.....)$