Question

Rezolvati ecuatiile:1/8+1/2*(2x-1)=2x-1/8*(8x-1)-1/4*(4x-2),va rog frumos,va dau coroana

Answer 1

[tex] \frac{1}{8} + \frac{1}{2} *(2x-1)=2x- \frac{1}{8}* (8x-1)- \frac{1}{4}*(4x-2)\\\\ \frac{1}{8} + \frac{1}{2} (2x-1)=2x- \frac{1}{8}(8x-1)- \frac{1}{4} *(4x-2)* \frac{1}{8}+ \frac{2x-1}{2}= \\\\=2x- \frac{8x-1}{8}- \frac{4x-2}{4} \\\\ \frac{2x-1}{2} -2x+ \frac{8x-1}{8} + \frac{4x-2}{4} =- \frac{1}{8} \\\\ \frac{4(2x-1)-2x*8+8x-1+2(4x-2)}8}=- \frac{1}{8}~~~~~~~~~|*8 \\\\ 8x-4-16x+8x-1+8x-4=-1\\\\ 8x-9=-1\\\\ 8x=-1+9\\\\ 8x=8\\\\ x= \frac{8}{8} \\\\ \bold{x=1}[/tex]

Answer 2

1|8+1|2x(2x-1)=2x-1|8x(8x-1)-1|4x(4x-2)⇒
1|8+2x+1|2=2x-8x+1||8-4x-2|4⇒
5+8x|8=16x-8x+1-8x-4|8⇒
5+8x|8=-3|8⇒
8(5+8x)=-8x3⇒
40+64x=-24⇒
64x=-40-24⇒64x=-64⇒x=-64|64⇒x=-1
succes