Question

Rezolvaţi ecuaţiile:

2 * (x + 2) - 6x + 12 = 3 * (5 - x)

Rezolvati urmatoarele ecuatii amplificandu-le cu un multipli comun al numitorilor tuturor termenilor din ecuaţie:

a). x-1/2 - 3x-2/4 = 2
b). 2x-1/10 - x/4 = 1 - 3x+1/8
c). 2/3 - x-1/6 + 4-3x/9 = x-5/2
d). 2 * 2x-1/3 - (x - 5) = x/8 + x+7/6
e). -2/3 = 4x+1/6 + 1/4 * (x+1) - 2

Dau coroană!

Answer 1

1.
2(x+2)-6x+12=3(5-x)
2x+4-6x+12=15-3x
-4x+16=15-3x
-4x+3x=15-16
-x=-1
x=1


2.
a)x-$\frac{1}{2}$-3x-$\frac{2}{4}$
-2x-1=2
-2x=2+1
-2x=3
x=-$\frac{3}{2}$

b)2x-$\frac{1}{10}$-$\frac{x}{4}$=1-3x+$\frac{1}{8}$
2x-$\frac{1}{10}$-$\frac{x}{4}$=$\frac{9}{8}$-3x
80x-4-10x=45-120x
70x-4=45-120x
70x+120x=45+4
190x=49
x=$\frac{49}{190}$

c)$\frac{2}{3}$-x-$\frac{1}{6}$+4-$\frac{3x}{9}$=x-$\frac{5}{2}$
$\frac{9}{2}$-x-$\frac{3x}{9}$=x-$\frac{5}{2}$
27-6x-2x=6x-15
27-8x=6x-15
-8x-6x=-15-27
-14x=-42
x=3

d)[tex]2*2x- \frac{1}{3} -(x-5)= \frac{x}{8} +x+ \frac{7}{6} [/tex]
$4x- \frac{1}{3} -x+5= \frac{x}{8} +x+ \frac{7}{6}$
[tex]3x+ \frac{14}{3} = \frac{x}{8} +x+ \frac{7}{6} [/tex]
[tex]72x+112=3x+24x+28 [/tex]
$72x+112=27x+28$
$72x-27x=28-112$
[tex]45x=-84 [/tex]