Question

Rezolvati ecuatiile:
6[(2x+1):3-53]+8<356
3(2x+7)-5=22
5[2(3x+2)-11]+4=29
2(3x-7)<10
Va rog ajutati-ma...Multumesc :)

Answer 1

=6[(2x+1)/3-53]<356-8
6[(2x+1-159)/3]<348
(2x-158)/3<348/6
(2x-158)/3<58
2x-158<58·3
2x<174+158
x<332/2
x<166
X∈(-α, 166)

3(2x+7)-5=22
6x+21=22+5
6x=27-21
x=6/6
x=1

2[2(3x+2)-11]+4=29
2(6x+4-11)=29-4
2(6x-7)=25
12x-14=25
12x=25+24
x=49/12

2(3x-7)<0
6x-14<0
6x<14
x<14/6
x<7/3