Question

Rezolvați ecuațiile:
8x+20=3x

(2+√3)x-2+√3=0

√3x+4=1-1√3x

Vă rog, repede!
DAU COROANĂ!!​

Answer 1

$8x + 20 = 3x \\ 8x - 3x = - 20 \\ 5x = - 20 \\ x = - 4$

$(2 + \sqrt{3} )x - 2 + \sqrt{3} = 0 \\ (2 + \sqrt{3} )x = 2 - \sqrt{3} \\ x = \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \\ x = {(2 - \sqrt{3} )}^{2} \\ x = 4 - 4 \sqrt{3} + 3 \\ x = 7 - 4 \sqrt{3}$

$\sqrt{3} x + 4 = 1 - 1 \sqrt{3} x \\ \sqrt{3} x + 1 \sqrt{3} x = 1 - 4 \\ 2 \sqrt{3} x = - 3 \\ x = - \frac{3}{2 \sqrt{3} } \\ x = - \frac{ \sqrt{3} }{2}$