Question

rezolvati ecuatiile a) 125+x/4-1/4=200 b) (3 1/8-x)-1 1/10=0 c) x-2/3-5/6=1/2 va rog, repede!

Answer 1

a) [tex] \frac{125+x}{4} - \frac{1}{4}=200 [/tex]
aducem la acelasi numitor adica 4 si vom avea
125+x-1=800
x=800-124
x=676

b) $(3* \frac{1}{8}-x)- \frac{11}{10}=0$
aducem la acelasi numitor comun adica 80
30-80x=88
-80x=88-30
-80x=58
$x= -\frac{58}{80} = -\frac{29}{40}$

c) $\frac{x-2}{3} - \frac{5}{6}= \frac{1}{2}$
aducem la acelasi numitor adica 6
2x-4-5=3
2x-9=3
2x=3+9
2x=12
x=12:2
x=6