Question

Rezolvati ecuatiile. a) (2x+3):2,5=6. b) 4x+2/5-2008⁰=1 4/5

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Answer 1

$a) (2x+3):2,5=6$

$(2x+3) \div \frac{5}{2} = 6$

$(2x+3) \times \frac{2}{5} = 6$

$\frac{4}{5} x + \frac{6}{5} = 6$

$4x + 6 = 30$

$4x = 30 - 6$

$4x = 24$

$x = 6$

$b) 4x+ \frac{2}{5} -2008⁰ = \frac{14}{5} </p><p>$

$4x + \frac{2}{5} - 1 = \frac{14}{5}$

$4x - \frac{3}{5} = \frac{14}{5}$

$4x = \frac{14}{5} + \frac{3}{5}$

$4x = \frac{17}{5}$

$x = \frac{17}{20}$