Question

rezolvati ecuatiile: a e N, 9+3a=24-2a, 4a-3=11-3a, (16:a+5)4=52, 5(a:4-10)=20, 5+8a=21+4a, 3a+12=44-5a, 6(a:3-17)=24, 3(17+36:a)=63

Answer 1

a) 9+3a=24-2a
9+24=3a-2a
a=33
b) 4a-3=11-3a
4a+3a=11+3
7a=14
a=14:7
a=2
c) (16:a+5)4=52
(16:a+5)=52:4
(16:a+5)=13
16:a=13-5
16:a=8
a=8•16
a=128
d) 5(a:4-10)=20
a:4-10=20:5
a:4-10=4
a:4=4+10
a:4=14
a=14•4
a=56
E) 5+8a=21+4a
21-5=8a-4a
16=4a
a=16:4
a=4
f)3a+12=44-5a
3a+5a=44-12
8a=32
a=32:8
a=4
g) 6(a:3-17)=24
a:3-17=24:6
a:3-17=4
a:3=4+17
a:3=21
a=21•3
a=63
h)3(17+36:a)=63
17+36:a=63:3
17+36:a=21
36:a=21-17
36:a=4
a=36•4
a=144