Question

Rezolvati ecuatiile:a) x+5/7=4/3;b)2intregi1/2+x=3intregi1/7;c) 3/4+x/4=7/4;d) x-3/11=2intregi1/11. Va rog mult ajutati-ma. Dau coroana.

Answer 1

a) x = 4/3 - 5/7
Numitor comun 21
21x=28-15
21x=13 =>x = 13/21

b) 5/2 + x = 22/7
Numitor comun 14
35+14x=44
14x=44-35 => x=9/14

c) Avand acelasi numitor, putem scrie :
3+x=7 => x=4

d) x - 3/11 = 23/11
Numitor comun 11
11x-3=23
11x=23+3 => x=26/11=2 intregi 4/11