Question

rezolvati ecuatiile exponentiale

$3^{x^2-5x+7} = 27$
$5*2^x + 3*2^x^+^1 - 2^x^+^2 = 2*3^x + 3^x^+^2 - 3^x^+^1$

Answer 1

$a) 3^{ x^{2} -5x+7} =3^3 \\ x^{2} -5x+7=3 \\ x^{2} -5x+4=0 \\ x=1;x=4 \\ b)2^x(5+6-4)=3^x(2+9-3) \\ 2^x*7=3^x*8 \\ (\frac{2}{3})^x= \frac{8}{7} \\ x= log_{ \frac{2}{3}} } \frac{8}{7}$