Question

Rezolvati ecuatiile in multimea numerelor reale :
a) 4(x+5)-5(x+3)=x-5
b) 3(2x+3)-2(3x+2)= -3(x+2)+2
c) -3x+5-4(x-1)= -2(x+1)-24​

Answer 1

a). 4(x+5)-5(x+3)=x-5

4x+20-5x+15=x-5

-x+35=x-5

-x-x=-35-5

-2x=-40÷(-2)

x=20

b). 3(2x+3)-2(3x+2)= -3(x+2)+2

6x+9-6x+-4=-3x-6+2

0+5=-3x-4

3x=-5-4

3x=-9÷3

x=-3

c). -3x+5-4(x-1)= -2(x+1)-24

-3x+5-4x+4=-2x-2-24

-7x+9=-2x-26

-7x+2x=-9-26

-5x=-35÷(-5)

x=7

Answer 2

Răspuns:

a)

4x+20-5x-15=x-5

-x+5=x-5

-2x+5=-5

-2x=-10

x=5

b)

6x+9-6x-4=-3x-6+2

5=-3x-4

9=-3x

x=-3

c)

-3x+5-4x+4=-2x-2-24

-7x+9=-2x-26

-5x=-35

x=7

Explicație pas cu pas: